A Bag Contains 5 Red Marbles And 4 Green Marbles

Also x 3 marbles have a scratch on them.

A bag contains 5 red marbles and 4 green marbles.

We will assume that only two marbles are drawn from the bag and hence there are two cases. Well in succession without replacement is more interesting and means the first blind draw is 5 12 chance as there are 12 total and 5 are green and your second draw there are 11 total but now only 4 of them are. What is the reasonable prediction for the number of times a green or black. What is the probability that neither marble is blue.

5 red marbles 6 blue marbles 3 green marbles 4 black marbles 2 yellow marbles a marble will be drawn from the bag and replaced 100 times. After choosing the red marble 8 marbles left. A bag contains 8 red marbles 4 white marbles and 5 blue marbles. A bag contains 4 green marbles 6 red marbles 14 orange marbles 5 brown marbles and 8 blue marbles.

Hence the probability of choosing a red marble then a green marble without replacement is. A bag contains 5 red marbles and 4 green marbles 9 marbles in total. You draw 4 marbles out at random without. Find p red and blue.

The required probability is. A are the four different colour outcomes equally likely. Total number of balls in the bag 5 4 9. A marble is chosen at random from the bag and not replaced.

The probability of choosing a red marble is given by. A bag contains five green marbles three blue marbles two red marbles and two yellow marbles. We are to find the probability of choosing a red marble then a green marble without replacement. Then the probability of choosing a green marble is.

In this bag with x 2 5 marbles total x 1 are red. You have a bag which contains only red and green marbles. If a marble is selected at random what is the probability that is is not blue. 5 red marbles 6 blue marbles 3 green marbles 4 black marbles 2 yellow marbles a marble will.

The probability of choosing a red marble is. B find the probability of drawing each colour marble i e p green p blue p red and p yellow c find the sum of their probabilities. Then a second marble is. A bag contains 9 red marbles 8 white marbles and 6 blue marbles.

The first marble is not returned in the bag before drawing the second. One marble is drawn out randomly. Given that a bag contains 5 red marbles and 4 green marbles. The first marble is returned in the bag before drawing the second.

The probability of drawing a red marble from the original bag is equal to that. You choose a marble replace it and choose again.