A Bag Contains Red And Blue Marbles Two Marbles Are Drawn Without Replacement

Number the red marbles 1 4 and the blue marbles 5 9.

A bag contains red and blue marbles two marbles are drawn without replacement.

Two marbles are drawn without replacement. On the other hand there are 9 choices for the first marble and 8. Drawing simultaneously is the same as sampling without. If replacement is not allowed what is the probability that the second marble drawn will be red.

Can someone please point why my solution is wrong. A bag contains red and blue marbles. Two marbles are drawn without replacement from an urn containing 4 red marbles 5 white marbles and 2 blue marbles. Two marbles are drawn without replacement.

P both red p second is red. A bag contains 4 red marbles and 5 blue marbles. P both red frac binom22. The first marble drawn is blue and the second is red.

Then there are 4 possibilities for drawing the first red marble and 3 possibilities for drawing the second red marble. The first marble drawn is red and the second is blue. A bag contains 3 white 4 black and 2 red marbles. I disagree with the given answer frac29.

P at least one red p rr or rb or br alternatively p at least one red 1 p no reds complementary events 1 p bb and so on. The probability of selecting a red marble on the first draw is 0 5. Two marbles are randomly drawn without replacement. Two marbles are drawn without replacement from a jar containing 4 black and 6 white marbles.

Two marbles are drawn from the bag. Determine the probability that at least one is red. A bag contains 5 red and 3 blue marbles. The probability of selecting a red marble and then a blue marble is 0 28.

B find probabilities for p bb p br p rb p ww p at least one red p exactly one red 3. A draw the tree diagram for the experiment. Two marbles are drawn simultaneously from the bag.